If20. On the numerical axis are three points: A, B, C. Determine which of the last two points (B or C) is closer to A, and display this point and its distance from point A.

**Solution in Python 3:**

import random

A,B,C = random.sample(range(-10, 10), 3)

print("Number A:", A)

print("Number B:", B)

print("Number C:", C)

AB = abs(A-B)

AC = abs(A-C)

print("Distance from A to B:",AB)

print("Distance from A to C:",AC)

if AB < AC:

print("В is closer to A")

elif AB > AC:

print("C is closer to A")

else:

print("B and C are equidistant to A")