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If20. On the numerical axis are three points: A, B, C. Determine which of the last two points (B or C) is closer to A, and display this point and its distance from point A.

Solution in Python 3:

import randomA,B,C = random.sample(range(-10, 10), 3)print("Number A:", A)print("Number B:", B)print("Number C:", C)AB = abs(A-B)AC = abs(A-C)print("Distance from A to B:",AB)print("Distance from A to C:",AC)if AB < AC:    print("В is closer to A")elif AB > AC:    print("C is closer to A")else:    print("B and C are equidistant to A")