While13. A number A (> 1) is given. Output the smallest integer K for which the sum 1 + 1/2 + ... + 1 / K is greater than A, and this sum itself.

Solution in Python 3:

import random

A = random.randrange(2,10)
A = 7
print('A = ', A)

K = 1.0
S = 1.0
while S <= A:
    K += 1
    x = 1/K
    S += 1/K
    print("K = {0}, 1/K = {1}, S = {2}".format(K,x,S))

print()
print("K = {0}, S = {1}".format(K,S))