If30. Given an integer lying in the range 1-999. Output its string-description of the form "even two-digit number", "odd three-digit number", etc.

Solution in Python 3:

L = [1,21,80,99,100,101,800,901,999]

for i in L:
    if i%2 == 0:
        s = "even "
    else:
        s = "odd "

    i_str = str(i)
    n = len(i_str)
    if n == 1:
        s += "one-digit "
    elif n == 2:
        s += "two-digit "
    elif n == 3:
        s += "three-digit "
    
    s += "number"
    print(i," : ",s)